3.06  Polynomial and Fractional Inequalities

            by Graphing Calculator Methods

College Algebra: One Step at a Time,  Pages 413 - 424:  29, 3 Extra Problems

Dr. Robert J. Rapalje

Seminole State College of Florida

Sanford, FL  32773

 

P. 423  #29.  Solve for x.  (Give the answer in interval notation.)

.

Solution:    First, you must set the inequality to zero by subtracting 1 from each side of the inequality. 

                       

Next, draw the graph of

   

Notice that the roots (or zeros) of this function are at x=-2 and x=6, and there are asymptotes at x=0 and x=4.   These zeros and asymptotes can and will be obtained algebraically.  Since the inequality is , you will be looking for values of x, where the graph is above the x axis

 

Since there are two roots (zeros) and two asymptotes, this gives you four endpoints on the number line, and five intervals to consider for your solution.  You must select the intervals that are ABOVE the x-axis.

 

In the first interval, from –infinity to -2, the graph is below the x-axis

In the second interval, from -2 to 0 the graph is above the x-axis. 

In the third interval, from 0 to 4, the graph is below the x-axis. 

In the fourth interval, from 4 to 6, the graph is above the x-axis.

In the fifth interval, from 6 to infinity, the graph is below the x-axis. 

 

Therefore the solution consists of the second and fourth interval, where the graph is above the x-axis (endpoints are NOT included in this one!). 

                                                       

FINAL ANSWER:       

 

—  Finding the Roots and Asymptotes Algebraically   —

1.  Asymptotes--Set denominators ¹ 0.

      Solve 

                       

                 

 

2.  Roots--Change the inequality to an equation and solve for x.

     Solve   .     Multiply both sides by the LCD = .

             

                       

                       

                               

Extra Problem 1 (By Vera).  Solve for x.  (Give the answer in interval notation.)

.

Solution:    First, you must set the inequality to zero by subtracting  from each side of the inequality and find the endpoints for the inequality. 

                       

Next, find the endpoints by

I.                    finding any values of y that make a denominator zero, and

II.                  solving the EQUATION .

I.  Solve

                          

                          

    II.   Solve

                         

                         

                      

                           

                          

So the endpoints are  and  .

Next, draw the graph of

 

   

Since the inequality is , you will be looking for values of x, where the graph is BELOW the x axis.  You must select the intervals that are BELOW the x-axis.

 

In the first interval, from –infinity to , the graph is below the x-axis

In the second interval, from  to 2, the graph is above the x-axis. 

In the third interval, from 2 to infinity, the graph is below the x-axis. 

 

Therefore the solution consists of the first and third interval, where the graph is below the x-axis (endpoints are NOT included!). 

                                

 

Extra Problem 2 (By Vera).  Solve for x.  (Give the answer in interval notation.)

.

Solution:    First, you must set the inequality to zero by subtracting  from each side of the inequality and find the endpoints for the inequality. 

                       

Next, find the endpoints by

I.                    finding any values of y that make a denominator zero, and

II.                  solving the EQUATION .

I.  Solve

                          

                          

    II.   Solve

                         

                         

                      

                           

                          

So the endpoints are  and  .

Next, draw the graph of

 

   

Since the inequality is , you will be looking for values of x, where the graph is BELOW the x axis.  You must select the intervals that are BELOW the x-axis.

 

In the first interval, from –infinity to , the graph is below the x-axis

In the second interval, from  to , the graph is above the x-axis. 

In the third interval, from  to infinity, the graph is below the x-axis. 

 

Therefore the solution consists of the first and third interval, where the graph is below the x-axis (endpoints are NOT included!). 

                                

 

p. 163.  #29. 

Extra Problem (by Aimee). 

Solve for x. Give the answer in interval notation.

.

Solution:    Start by drawing the graph of

     

Notice that the roots (or zeros) of this function are at x=8 and x=-5, and there is an asymptote at x=3.   Since the inequality is , you will be looking for values of x, where the graph is on or above the x axis

The graph has roots at x=-5 and 8.  The vertical line at x=3 is not really a part of the graph, but it is an asymptote, a line that the graph approaches by never actually touches.

Since there are two roots (zeros) and one asymptote, this gives you three endpoints on the number line, and four intervals to consider for your solution.  You must select the intervals that are ON or ABOVE the x-axis.

In the first interval, from –infinity to -5, the graph is below the x-axis

In the second interval, from -5 to 3 the graph is above the x-axis. 

In the third interval, from 3 to 8, the graph is below the x-axis. 

In the fourth interval, from 8 to infinity, the graph is above the x-axis.

Therefore the solution consists of the second and fourth interval, where the graph is above the x-axis, including the endpoints at x=-5 and x=8, since these are points that are ON the x-axis. 

                                             

                                                     

 

 

  

Return to main page        Math in Living C O L O R !!

     Return to Intermediate Algebra page  

 Return to College Algebra page

 

Dr. Robert J. Rapalje Altamonte Springs Campus
Contact me at:   rapaljer@seminolestate.edu
Phone number:  NONE Retired!!
OFFICE:          NONE  
Copyright © Seminole State College of Florida, 1997