2.09 Quadratic Equations by Factoring
Basic
Algebra: One Step at a Time. Pages
185-192: #21, 22, 23, 25, 26, 27, 28, 30, 34, 37, 38, 42, 46, 55, 56
Dr. Robert J. Rapalje
Seminole State College of Florida
Sanford, FL 32773
To see
Section 2.09, with
detailed explanations, examples, exercises, and answers,
click here!
21.
Solution:
The first step will be to remove parentheses by the Distributive
Property.

Next, you
must set the equation equal to zero. The easiest way to do this is to add
to each side of the equation.
Now,
factor the trinomial, using
9
and 3,
with opposite signs.

Set each factor equal to zero.
or

Final
Answer: 
22.
Solution:
The first step is to set the equation equal to zero. To do this,
you can add
and subtract
from
each side:

Now, factor
the trinomial, using
9
and
2,
with opposite signs.

Set each
factor equal to zero.
or

Final
Answer: 
23.
Solution:
The first step will be to remove parentheses by the Distributive
Property.

Next, you
must set the equation equal to zero. There are two methods! You decide
which way you think is easier!!
METHOD I: In order to set the equation equal to zero with a POSITIVE
coefficient of
,
take everything to the RIGHT side of the equation!


Now, factor
the trinomial, using
10
and
4,
with opposite signs.

Set each
factor equal to zero.
or

Final
Answer: 
METHOD
II: 
In order to
set the equation equal to zero you may choose to add
to each side of the equation


In order to
factor this, you may want to multiply both sides of the equation by
(-1).


Now, factor
the trinomial, using
10
and
4,
with opposite signs.

Set each
factor equal to zero.
or

Final
Answer: 
25.
Solution:
Since this equation is already equal to zero, the first step will
be to factor the left side. The first step in any factoring problem is to
try to take out a common factor. In this case the common factor is


Set each
factor equal to zero:

Final
Answer: 
26.
Solution:
Since this equation is already equal to zero, the first step will
be to
FACTOR the left side. The first step in any factoring problem is to try
to take out a common factor. In this case the common factor is


Set each factor equal to zero:

Final Answer: 
27.


Notice that this is really
just a TRINOMIAL,
and as such, it can be factored into the product of two binomials. In this
case, the
FIRST times
FIRST
gives you
which
is
.

Next, the
LAST times
LAST must give you
,
so try
or
,
where the numbers are the SAME sign. In order for the numbers to add and
give you a
you
will need to put the
in
the first binomial and the
in
the second binomial.
Then the OUTER
times OUTER will be
,
and the INNER times INNER will be
for
a total of
.
It looks like this:

Now, set each factor equal to
zero, and solve for x. There are two solutions:

28.
Solution:
The first step is to multiply out the parentheses and set the
equation equal to zero by subtracting
2 from each side of the equation.


The next
step is to factor the resulting trinomial. There is no common factor, so it
must begin like this:


Final
Answer: 
30.
Solution:
The first step is to multiply out the parentheses and set the
equation equal to zero by subtracting
5 from each side of the equation.


The next
step is to factor the resulting trinomial. There is no common factor, so it
must begin like this:


Final
Answer: 
34.
Since
the equation is already set equal to zero, the first step is to
FACTOR
the left side of the equation. There IS a common factor of
5x,
so the first step in factoring must be to take out the common factor of
5x.


The next step is to factor the resulting trinomial. There looks like this::



Final Answer: 
37.
Solution:
Since this equation is already equal to zero, the first step will
be to factor the left side. The first step is to notice the
.
Unfortunately, you can’t take out a common factor, so it looks like an
“advanced trinomial factoring” problem. However, it might not be too bad!
Notice the perfect squares on each end of this trinomial. Maybe it’s a
perfect square trinomial! Let’s try that first. Anyway, set up the two
sets of parentheses, and prepare to factor the trinomial however it works
out!


First times
First
will be
2x
times 2x.

Last times
Last
will be
5 times 5.
OR

Set each
factor equal to zero.

Final
Answer:
Final
Answer:
38.
Solution:
First, you must set the equation equal to zero. Do this by adding
to each side.

The first
step will be to factor the left side. The first step is to notice the
.
Unfortunately, you can’t take out a common factor, so it looks like an
“advanced trinomial factoring” problem. However, it might not be too bad!
Notice the perfect squares on each end of this trinomial. Maybe it’s a
perfect square trinomial! Let’s try that first. Anyway, set up the two
sets of parentheses, and prepare to factor the trinomial however it works
out!


First times
First
will be
2x
times 2x.

Last times
Last
will be
3 times 3.
OR

Set each
factor equal to zero.

Final
Answer:
Final
Answer:
42.
Solution:
Since this equation is already equal to zero, the first step will
be to factor the left side. Remember
FCFF?
Factor the
Common
Factor
First!! Factor out the common factor of
x.

Next,
notice that you have a difference of two squares!


Notice that
there are 3 factors (in keeping with an
equation). Set each factor equal to zero.
Final
Answer:
46.
Solution:
Since this equation is already equal to zero, the first step will
be to factor the left side. Remember
FCFF?
Factor the
Common
Factor
First!! Factor out the common factor of
x2.


Notice that
there are 3 factors (in keeping with an
equation). Set each factor equal to zero.
Final
Answer:
NOTE: The
answer of
is
repeated to illustrate the 3 solutions for this
equation.
55.
Solution:
The first step in
solving this equation is to square the binomial—i.e., remove the
parentheses:


The next step is to set the equation equal to zero, by subtracting
from
each side:


Notice
that this is a
trinomial
which factors:


Therefore,

56.
Solution:
The first step in
solving this equation is to square the binomial—i.e., remove the
parentheses:


The next step is to set the equation equal to zero, by subtracting
and
adding
from
each side:


Notice that this is a trinomial
which factors:

Therefore,

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