2.09   Quadratic Equations by Factoring

from Basic Algebra: One Step at a Time © 2002

P. 185-192

Dr. Robert J. Rapalje

Seminole State College of Florida

 

ANSWERS TO ALL EXERCISES ARE INCLUDED AT THE END OF THIS PAGE

 

To see selected solutions in Living C O L O R  click here!

 

A great deal of effort has just been spent learning to factor algebraic expressions.  The question has probably been raised more than once, "What good is factoring?"  Many situations arise in math in which it is necessary to use the factored form of an expression.  One such situation is solving a quadratic equation−−an equation in which the variable is raised to the second power.  In general, the equation is in the form ax2+bx+c=0.  Before solving quadratic equations by the method of factoring, it is necessary to remember one very important fact about numbers: If the product of two numbers is zero, then one of the numbers must be zero.  First notice that this is a special property of zero, and there is no other number of which this could be said.  Secondly, notice that in order to use this property, it is necessary to use a product (i.e., factored form) of numbers.  Of course, this is where the process of factoring comes in.

 PRINCIPLE

                           IF    x@y = 0,   THEN  x=0   OR   y=0

 

 EXAMPLE 1. Solve   x2 + 3x = 0

Solution:         Factor  x(x + 3) = 0   This is a product equal to zero.

                                    x=0 or x+3 = 0   Set each factor equal to zero.

                                                   −3   −3   Solve for  x  in each case.

                                    x = 0;      x = −3

 You may wish to check these answers in the original equation.

Check:             x = 0                            x = − 3

02 +3(0) = 0        (−3)2 + 3(−3) = 0

        0    = 0          9 + (−9) = 0                       

 

EXAMPLE 2.   Solve   x2 + 3x = 4

Solution:         Notice that this equation does not equal zero.  The first step is to make it equal to zero by adding −4 to each side:    

       x2 + 3x − 4  = 0

                        Factor:     (x + 4)(x − 1) = 0

                        At this point it may be helpful to think of splitting the problem in half.  Think of exchanging the one "large" equation for two "small" ones, as shown below:

                                          (x + 4)(x − 1) = 0

                                    x + 4 = 0     x − 1 = 0   Set each factor equal to 0.

                                       −4   −4         +1   +1  Solve for  x  in each case.

                                            x = −4      x  = 1

 Again, you may wish to check the answers (use original equation).

 

                                   SUMMARY QUADRATIC (x2) EQUATIONS  BY FACTORING 

Step 1:   Must equal zero

Step 2:   Must be in factored form

Step 3:   Set each factor equal to zero, and solve the "small"  equations.

 

EXERCISE.     Solve the following quadratic equations.

1.         x2 + 5x = 0                      2.            x2 − 6x = 0                       3.           x2 − 8x = 0

     x(             ) = 0                           ____(            ) = 0                                   x(                ) = 0      

 ____ = 0    (            ) = 0             

                        x = ____

 

4.         x2 + 2x − 8 = 0                5.         x2 − 6x − 40 = 0                  6.  x2 + 5x + 6 = 0    

           (           )(          ) = 0                 (            )(           ) = 0               (            )(            ) = 0

  (            ) = 0   (            ) = 0  

         x = ____    x = ____

 

 7.        x2 − 49 = 0                        8.          x2 − 25 = 0                         9.     x2 − 169 = 0

 

 

 

 

10.       x2 − 4x − 5 = 0                   11.       x2 − 3x − 10 = 0               12.     x2 + 3x − 10 = 0

 

 

 

 

   

 

In the next exercises, remember the first step must be to set the equation equal to zero.

13.       x2 + 2x = 24                       14.         x2 + 5x  = 14                  15.      x2 − 10x  = −21     

x2 + 2x − 24 = 0

            (           )(          )=0

 

 

 [Caution: In #16,  when you add −7x to the left side, does it matter where you put it?]

 16.       x2 + 12 = 7x                       17.       x2 + 5  =  − 6x                  18. x2 − 12  =  − x

 

 

 

 

After some practice, you will probably find that it is not necessary to show as many steps in solving problems.  The next two examples illustrate the way we usually show the work.

EXAMPLE 3.  Solve for x:   x2 + 21x = 100     EXAMPLE 4.  Solve for x:   (x−3)(x−4) = 2

Solution:                          x2 + 21x − 100 = 0                                                x2 − 7x + 12 = 2

    (x + 25)(x − 4) = 0                                                 x2 − 7x + 10 = 0

                                          x = 25  or  x = 4                                                (x − 5)(x − 2) = 0

                                                                                                                       x = 5  or  x = 2

 

19.       x(x + 4) = 5                        20.         x(x + 5)  = 6                   21.       3 (2x − 9) = − x2

            x2 + 4x − 5 = 0

 

 

 

 

22.       7x = 18 −  x2                     23.          x (6 − x) = − 40              24.        x (5 − x) = − 50

 

 

 

 

 

25.       2x2 − 3x  =  0                    26.         5x2 + 4x = 0                    27.       x(2x + 7) = −5

 

 

 

 

 

28.       x(3x + 1) = 2                      29.            x(5x − 1)  = 6              30.       x(2x − 9) = 5

 

 

 

 

 

 

In the next exercises, remember to factor the common factor first.

31.          5x2 + 20x + 15 = 0                                       32.       2x2 − 22x + 48 = 0

            5(                              ) = 0

         5  (             )(             ) = 0

   5¹0   x +    0       x +       = 0

                x =              x =

 Since 5¹0, there are only two

solutions, x=____ or _____             

 

33.          x3 − 11x2 + 24x = 0                                     34.       5x3 + 20x2 + 15x = 0

            x(                        ) = 0

            x(            )(          ) = 0

      x = 0    x −    = 0    x −      = 0

 

      x = 0      x =             x =

 

There are three solutions:

 

x=____ , _____, or _____

Compare and contrast #31−32 with #33−34.  Notice that a linear equation (with x only) usually has one solution, a quadratic equation (with x2) usually has two solutions, a cubic equation (with x3) usually has three solutions, etc.  Notice that the constant factor in #31−32 has no effect on the solutions.  However, if the monomial factor has a variable (as in #33−34), it is a solution, and it therefore cannot be ignored. 

 

Does it seem that all quadratic equations have two solutions?  Consider the following:

35.           x2 − 6x + 9 = 0                                            36.       x2 + 10x + 25 = 0  

            (         )(         ) = 0

            x= ____  x= ____

(It is not necessary to write the answer twice!)

  

37.       4x2 + 20x + 25 = 0                                          38.       4x2 + 9 = 12x      

 

 

 

 

 

Although each of the last four exercises is quadratic, each has a single solution that occurrs twice.  In higher math courses, we call the solutions to an equation the roots of the equation.  When an answer occurs twice, as in these exercises, we call it a double root.

It is also possible that the quadratic equation does not factor.  These equations can be solved by other methods (see Completing the Square and Quadratic Formula) that will be explained later.  Sometimes there is no real solution.  For example, x2 + 4 = 0 has no real solution.  It does not factor (does it?).  Besides, what real number can you square, then add 4 and still end up with zero.  If you square a negative number, you get a positive; if you square a positive number, you get a positive number; and if you square 0 you get 0.  And in all of these cases, if you add 4 to the result, you certainly do not get 0.  Therefore, there is no real solution.

EXERCISES. Solve the equations:

39.       x3 + 5x2 + 4x = 0                                             40.   x3 − 8x2 + 7x = 0          

 

 

 

 

41.       x3 − 9x = 0                                                      42.   x3 − 25x = 0          

 

 

 

  

43.       3x2 − 75 = 0                                                    44.   3x3 − 75x = 0           

 

  

 

 

 

45.       x3 − 12x2 + 36x = 0                                         46.   x3 − 9x2 = 0          

 

 

 

 

 

47.       x (x + 2) = 8                                                    48.       x (x − 2) = 8               

 

 

 

 

49.       (x−3)(x+3) = 8x                                              50.       (x−3)(x−2) = 12                     

 

 

 

 

51.       x2 = 4(3 − x)                                                    52.       x2 = 4(3 + x)

 

 

                

 

53.       2x2 = 3 + 5x                                                     54.       2x2 = 5x − 3    

 

 

  

 

55.       (x − 4)2  = 2x                                                   56.       (x − 4)2   =  32  −  2x            

 

 

 

 

 

 

57.       x(x−4) = −2x + 8                                             58.       2x (x + 5) = 3x + 15

 

 

 

 

ANSWERS 2.09

p. 186-192:      (NOTE:  Answers may be given in any order!)

              1. 0, -5;  2. 0, 6;  3.  0, 8;  4. -4, 2;  5. 10, -4; 6. -2, -3; 7. 7, -7;  8. 5, -5;  9. 13, -13;

            10. 5,-1; 11. 5,-2; 12. -5,2;  13. -6,4; 14. -7, 2; 15. 3,7; 16. 4,3;  17. -5,-1; 18. -4,3;

            19. -5, 1; 20. -6, 1;  21. -9, 3;  22. -9, 2;  23. 10, -4;  24. 10, -5;  25. 0, 3/2;  26. 0, -4/5;      

            27. -5/2, -1;  28. 2/3, -1;  29. 6/5, -1;  30. -1/2, 5;  31. -3, -1;  32. 8, 3;  33. 0, 8, 3;  

            34. 0, -3, -1; 35. 3;  36. -5;  37.  -5/2;  38. 3/2;  39. 0, -4, -1;  40. 0, 7, 1;  41. 0, 3, -3;

            42. 0, 5, -5;  43. 5, -5;  44. 0, 5, -5;  45. 0, 6;   46. 0, 9;   47. -4, 2;   48. 4, -2;   49. 9, -1;

            50. 6, -1;  51. -6, 2;  52. 6, -2;  53. -1/2, 3;  54. 3/2, 1;  55. 8, 2;  56. 8, -2;   57. 4, -2;         

            58. 3/2, -5.

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Dr. Robert J. Rapalje Altamonte Springs Campus
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