2.09
Quadratic Equations by Factoring
from Basic Algebra: One Step at
a Time © 2002
P.
185-192
Dr. Robert J. Rapalje
Seminole State College of Florida
ANSWERS TO ALL EXERCISES ARE INCLUDED AT THE
END OF THIS PAGE
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A great deal of
effort has just been spent learning to factor algebraic expressions.
The question has probably been raised more than once,
"What
good is factoring?" Many situations arise in math in which it is
necessary to use the factored form of an expression. One
such situation is solving a quadratic equation−−an equation in
which the variable is raised to the second power. In general, the
equation is in the form ax2+bx+c=0.
Before solving quadratic equations by the method of factoring, it
is necessary to remember one very important fact about numbers: If
the product of two numbers is zero, then one of the numbers must
be zero. First notice that this is a special property of
zero, and there is no other number of which this could be
said. Secondly, notice that in order to use this property, it is
necessary to use a product (i.e., factored form) of numbers. Of
course, this is where the process of factoring comes in.
PRINCIPLE
IF x@y
= 0, THEN x=0 OR y=0
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EXAMPLE 1. Solve x2
+ 3x = 0
Solution:
Factor x(x + 3) = 0 This is a product equal to
zero.
x=0 or x+3 = 0 Set
each factor equal to zero.
−3 −3 Solve for x
in each case.
x = 0; x = −3
You may wish to check
these answers in the original equation.
Check: x
= 0 x = − 3
02 +3(0)
= 0 (−3)2 + 3(−3) = 0
0 = 0 9
+ (−9) = 0
EXAMPLE 2.
Solve x2
+ 3x = 4
Solution:
Notice that this equation does not equal zero. The first step is to make
it equal to zero by adding −4 to each side:
x2
+ 3x − 4 = 0
Factor: (x + 4)(x − 1) = 0
At this point it may be helpful to think of splitting the problem in
half. Think of exchanging the one "large"
equation for two "small"
ones, as shown below:
(x + 4)(x − 1) = 0
x + 4 = 0 x −
1 = 0 Set each factor equal to 0.
−4 −4 +1
+1 Solve for x in each case.
x = −4 x = 1
Again, you may wish to check
the answers (use original equation).
SUMMARY
QUADRATIC (x2) EQUATIONS BY FACTORING
Step 1: Must
equal zero
Step 2: Must be
in factored form
Step 3:
Set each factor equal to zero, and solve the
"small"
equations.
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EXERCISE. Solve
the following quadratic equations.
1. x2
+ 5x = 0 2. x2
− 6x = 0 3. x2
− 8x = 0
x( 



)
= 0 ____( ) = 0
x( ) = 0 

____
= 0 
( ) = 0 
x = ____


4. x2
+ 2x − 8 = 0 5. x2
− 6x − 40 = 0 6. x2
+ 5x + 6 = 0
( )( ) = 0 ( )(
)
= 0
(
)( ) = 0
( ) = 0
( ) = 0
x =
____ x = ____
7. x2
− 49 = 0 8. x2 −
25 = 0 9. x2 − 169 =
0
10. x2
− 4x − 5 = 0 11. x2
− 3x − 10 = 0 12. x2
+ 3x − 10 = 0
In the next exercises,
remember the first step must be to set the equation equal to zero.
13. x2
+ 2x = 24 14. x2
+ 5x = 14 15. x2
− 10x = −21
x2 +
2x − 24 = 0
(
)( )=0
[Caution:
In #16, when you add −7x
to the left side, does it matter where you
put it?]
16. x2
+ 12 = 7x 17. x2
+ 5 = − 6x 18. x2
− 12 = − x
After some practice, you will
probably find that it is not necessary to show as many steps in solving
problems. The next two examples illustrate the way we usually show
the work.
EXAMPLE 3. Solve
for
x: x2 + 21x
= 100 EXAMPLE 4. Solve for x:
(x−3)(x−4) = 2
Solution:
x2 + 21x − 100 = 0
x2 − 7x + 12 = 2
(x
+ 25)(x − 4) = 0
x2 − 7x + 10 = 0
x = −25 or x = 4
(x − 5)(x − 2) = 0
x = 5 or x = 2
19. x(x
+ 4) = 5 20. x(x
+ 5) = 6 21. 3 (2x − 9) = − x2
x2
+ 4x − 5 = 0
22. 7x =
18 − x2 23. x
(6 − x) = − 40 24. x (5 −
x) = − 50
25. 2x2
− 3x = 0 26. 5x2
+ 4x = 0 27. x(2x
+ 7) = −5
28. x(3x
+ 1) = 2 29. x(5x
− 1) = 6 30. x(2x − 9) = 5
In the next exercises,
remember to factor the common factor first.
31. 5x2
+ 20x + 15 = 0 32.
2x2 −
22x + 48 = 0
5( ) = 0
5 (
)( ) = 0
5¹0 x
+ 0
x + = 0
x = x =
Since
5¹0,
there are only two
solutions, x=____
or _____
33. x3
− 11x2 +
24x = 0 34. 5x3
+ 20x2 +
15x = 0
x(
) = 0
x(
)( ) = 0
x = 0
x − = 0 x − = 0
x =
0 x = x =
There are three solutions:
x=____ , _____,
or _____
Compare and contrast #31−32
with #33−34. Notice that a linear equation (with x only)
usually has one solution, a quadratic equation (with x2)
usually has two solutions, a cubic equation (with x3)
usually has three solutions, etc. Notice that the constant factor in
#31−32 has no effect on the solutions. However, if the monomial factor
has a variable (as in #33−34), it is a solution, and it therefore cannot
be ignored.
Does it seem that all
quadratic equations have two solutions? Consider the following:
35. x2
− 6x + 9 = 0 36.
x2 +
10x + 25 = 0
(
)( ) = 0
x=
____ x= ____
(It is not necessary to write
the answer twice!)
37. 4x2
+ 20x + 25 = 0 38.
4x2 + 9 = 12x
Although each of the
last four exercises is quadratic, each has a single solution
that occurrs twice. In higher math courses, we call the solutions to an
equation the roots of the
equation. When an answer occurs twice, as in these exercises,
we call it a double root.
It is also possible
that the quadratic equation does not factor. These equations can be
solved by other methods (see
Completing the Square and
Quadratic Formula)
that will be explained later. Sometimes there is no real solution. For
example, x2
+ 4 = 0 has no real solution. It does not factor (does it?). Besides,
what real number can you square, then add 4 and still end up with zero.
If you square a negative number, you get a positive; if you square a
positive number, you get a positive number; and if you square 0 you get
0. And in all of these cases, if you add 4 to the result, you certainly
do not get 0. Therefore, there is no real solution.
EXERCISES. Solve the
equations:
39. x3
+ 5x2
+ 4x = 0 40.
x3 − 8x2
+ 7x = 0
41. x3
− 9x = 0
42. x3
− 25x = 0
43. 3x2
− 75 = 0 44. 3x3
− 75x = 0
45. x3
− 12x2
+ 36x = 0 46.
x3 − 9x2
= 0
47. x
(x + 2) = 8
48. x
(x − 2) = 8
49. (x−3)(x+3)
= 8x 50.
(x−3)(x−2) = 12
51. x2
= 4(3 − x)
52. x2
= 4(3 + x)
53. 2x2
= 3 + 5x 54. 2x2
= 5x − 3
55. (x − 4)2
= 2x 56.
(x − 4)2 = 32 − 2x
57. x(x−4)
= −2x + 8 58.
2x (x + 5) = 3x + 15
ANSWERS 2.09
p. 186-192: (NOTE:
Answers may be given in any order!)
1.
0, -5;
2. 0, 6; 3. 0, 8; 4. -4, 2;
5. 10, -4; 6.
-2, -3; 7. 7, -7; 8. 5, -5; 9. 13, -13;
10. 5,-1; 11. 5,-2; 12. -5,2; 13. -6,4;
14. -7, 2; 15. 3,7; 16. 4,3; 17. -5,-1;
18. -4,3;
19. -5,
1; 20. -6, 1; 21. -9, 3; 22. -9, 2; 23.
10, -4; 24. 10, -5; 25. 0, 3/2; 26.
0, -4/5;
27. -5/2,
-1; 28. 2/3, -1; 29. 6/5, -1; 30. -1/2, 5;
31. -3, -1; 32. 8, 3; 33. 0, 8, 3;
34. 0,
-3, -1; 35. 3; 36. -5; 37. -5/2; 38.
3/2;
39. 0, -4, -1; 40. 0, 7, 1; 41. 0, 3, -3;
42.
0, 5, -5; 43. 5, -5; 44. 0, 5, -5; 45. 0, 6; 46.
0, 9; 47. -4, 2; 48. 4, -2; 49. 9, -1;
50. 6, -1; 51. -6, 2; 52. 6, -2; 53.
-1/2, 3; 54. 3/2, 1; 55. 8, 2; 56. 8, -2;
57. 4, -2;
58. 3/2,
-5.
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